Các câu hỏi tương tự
\(\frac{1717}{1212}x+\frac{1717}{2020}x+\frac{1717}{3030}x=\frac{17}{6}\)
giải cả bài nhé
\(\frac{1717}{1212}x+\frac{1717}{2020}x+\frac{1717}{3030}x=\frac{17}{6}\)
giải cả bài nhé
tính giá trị biểu thức sau:\(\frac{3}{7}-\frac{3}{17}+\frac{3}{171}-\frac{3}{1717}\)\(\div\frac{9}{7}-\frac{9}{17}+\frac{9}{171}-\frac{9}{1717}\)
\(\left(\frac{151515}{161616}+\frac{17^9}{17^{10}}\right)-\left(\frac{1500}{1600}-\frac{1616}{1717}\right)\)
tinh nhanh
\(\left(\frac{151515}{161616}+\frac{17^5}{17^{10}}\right)+\left(\frac{1616}{1717}-\frac{1500}{1600}\right)\)
so sánh \(\frac{121212}{171717}+\frac{2}{17}-\frac{404}{1717}\)với B=\(\frac{10}{17}\)
A=\(\frac{7}{4}x\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\)
\(\frac{1414+1515+1616+1717+1818+1919}{2020+2121+2222+2323+2424+2525}\)
So sánh hai biểu thức:
A=\(\frac{121212}{171717}+\frac{2}{17}-\frac{404}{1717}\)với B=\(\frac{10}{17}\)