Các câu hỏi tương tự
Tim x , biet
c) x - \(\frac{5}{7}=\frac{2}{7}.\frac{11}{5}\)
d) \(\frac{2x}{5}=\frac{6}{2x-1}\)
tìm x trong các tỉ lệ thức sau :
\(a. \frac{x+5}{x+9}=\frac{x+4}{x+3}\)
\(b. \frac{2x-7}{2x+11}=\frac{5-3x}{4-2x}\)
\(c. \frac{3x+5}{-3x+11}=\frac{7x-5}{7-7x}\)
\(d. \frac{5x-3}{x+1}=\frac{5x-7}{x-1}\)
tìm xin Q,biết: a,frac{x}{2}left(frac{3x}{5}right)-frac{13}{5}-left(frac{7}{5}+frac{7}{10}xright)b,frac{2x-3}{3}+frac{-3}{2}frac{5-3x}{6}-frac{1}{3}c,left(frac{3}{2}-frac{2}{-5}right):x-frac{1}{2}frac{3}{2}d,frac{13}{x-1}+frac{5}{2x+2}-frac{6}{3x-3}e,left(frac{3}{2}-frac{5}{11}-frac{3}{13}right)left(2x-2right)left(frac{-3}{4}+frac{5}{22}+frac{3}{26}right)Ai bt câu nào làm câu đấy nhé ! Làm hết cũng đc nhé!
Đọc tiếp
tìm x\(\in\) Q,biết:
a,\(\frac{x}{2}\left(\frac{3x}{5}\right)-\frac{13}{5}=-\left(\frac{7}{5}+\frac{7}{10}x\right)\)
b,\(\frac{2x-3}{3}+\frac{-3}{2}=\frac{5-3x}{6}-\frac{1}{3}\)
c,\(\left(\frac{3}{2}-\frac{2}{-5}\right):x-\frac{1}{2}=\frac{3}{2}\)
d,\(\frac{13}{x-1}+\frac{5}{2x+2}-\frac{6}{3x-3}\)
e,\(\left(\frac{3}{2}-\frac{5}{11}-\frac{3}{13}\right)\left(2x-2\right)=\left(\frac{-3}{4}+\frac{5}{22}+\frac{3}{26}\right)\)
Ai bt câu nào làm câu đấy nhé ! Làm hết cũng đc nhé!
Bài 8: Tìm số nguyên x biết
a) \(\left(\frac{-12}{27}+\frac{2}{3}\right)+\frac{-2}{9}\le x\le\left(\frac{11}{7}+\frac{2}{5}\right)+\frac{7}{5}+\frac{3}{7}\) b\(\frac{-x}{2}+\frac{2x}{3}+\frac{x+1}{4}+\frac{2x+1}{6}=\frac{8}{3}\)
c)\(\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{12}{26}\)
x+35=17-x2x-23=-x-23x-11=33+5x13-(2x+5)=21+(22-x)(2x-9)-62=-5x+615+(-x+7)=-46-(-2x+7)x+30%x=-1,3x-25%x=\(\frac{1}{2}\)\(\frac{2}{3}\)x+\(\frac{1}{2}x=\frac{5}{2}\)\(\frac{2}{3}x=\frac{5}{12}+\frac{1}{2}x\)
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bài 3
d) \(\left(\frac{4}{5}\right)^{2x+7}=\frac{625}{256}\)
e) \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+2}}{131}\)
a)\(x-\frac{4}{5}=\frac{5}{7}\);b)\(5x=\frac{-1}{5}+\frac{11}{5}\); c)\(\frac{5}{3}-x=7+\frac{4}{5}\);d)\(\frac{-5}{11}+2x=\frac{7}{22}\)
CAC BAN GIUP MINH NHE MINH DANG CAN GAP
1 tìm x biết ;a, 0-|x + 1| 5 b, 2 - | frac{3}{4}- x | frac{7}{12}c, 2 | frac{1}{2}x - frac{1}{3}| - frac{3}{2} frac{1}{4}d, | x - frac{1}{3}| frac{5}{6}e, frac{3}{4}- 2 | 2x - frac{2}{3}| 2f, frac{2x-1}{2} frac{5+3x}{3}
Đọc tiếp
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;a, 0-|x + 1| 5 b, 2 - | frac{3}{4}- x | frac{7}{12}c, 2 | frac{1}{2}x - frac{1}{3}| - frac{3}{2} frac{1}{4}d, | x - frac{1}{3}| frac{5}{6}e, frac{3}{4}- 2 | 2x - frac{2}{3}| 2f, frac{2x-1}{2} frac{5+3x}{3}
Đọc tiếp
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)