a. x=(x-1)^2
b. câu hỏi chưa xong kìa
(x-1)3\(=\)(x-5)3
\(\Leftrightarrow\)(x-1)3-(x-1)5\(=\)0
\(\Leftrightarrow\)(x-1)3\([\)1-(x-1)2\(]\)\(=\)0
\(\Leftrightarrow\)(x-1)3\(=\)0 hoặc 1-(x-1)2\(=\)0
\(\Leftrightarrow\)x-1\(=\)0 hoặc x-1\(=\pm\)1
\(\Leftrightarrow\)x\(=\)1 hoặc x\(=\)2; x\(=\)0
Vậy x\(\in\){1;2;0}
b) (x-1)n\(=\)(x-1)n+2
\(\Leftrightarrow\)(x-1)n-(x-1)n+2\(=\)0
\(\Leftrightarrow\)(x-1)n\([\)1-(x-1)2\(]\)\(=\)0
\(\Leftrightarrow\)(x-1)n\(=\)0 hoặc (x-1)2\(=\)1
\(\Leftrightarrow\)x\(=\)1 hoặc x\(=\)2; x\(=\)0
Vậy x\(\in\){1;2;0}