a) (2x+3)-(5x-17)=9
2x+3-5x+17=9
-3x+20=9
-3x=9-20=-11
=>x=11/3
b) \(\left(\frac{1}{5}+\frac{4}{5}x\right)-\left(\frac{2}{5}x+\frac{1}{9}\right)=\frac{3}{7}\)
=> \(\frac{1}{5}+\frac{4}{5}x-\frac{2}{5}x-\frac{1}{9}=\frac{3}{7}\)
=> \(\left(\frac{1}{5}-\frac{1}{9}\right)+\left(\frac{4}{5}x-\frac{2}{5}x\right)=\frac{3}{7}\)
\(\frac{4}{45}+\frac{2}{5}x=\frac{3}{7}\)
\(\frac{2}{5}x=\frac{3}{7}-\frac{4}{45}=\frac{107}{315}\)
x=107/315:2/5=107/126
dễ tí nữa tôi lấy nk khác của tôi làm thì và kb nhé
a) = 2x-5x+3+17=9\(\Rightarrow\)-3x+20=9\(\Rightarrow\)-3x=-11\(\Rightarrow\)x=11/3
b) = \(\frac{1}{5}-\frac{1}{9}+\frac{4}{5}x-\frac{2}{5}x=\frac{3}{7}\Rightarrow\frac{4}{45}+\frac{2}{5}x=\frac{3}{7}\Rightarrow\frac{2}{5}x=\frac{107}{315}\Rightarrow x=\frac{107}{126}\)
a,(2.x+3) - (5.x-19)=9 2.x-5.x+3-19 =9 -3.x+(-16) =9 -3.x =25 x =25:(-3) x =\(\frac{25}{-3}\) b,\(\left(\frac{1}{5}+\frac{4}{5}x\right)-\left(\frac{2}{5}x+\frac{1}{9}\right)=\frac{3}{7}\) \(\frac{4}{5}x-\frac{2}{5}x-\frac{1}{5}-\frac{1}{9}=\frac{3}{7}\) \(\frac{2}{5}x-\frac{4}{45}=\frac{3}{7}\) \(\frac{2}{5}x=\frac{3}{7}+\frac{4}{45}\) \(\frac{2}{5}x=\frac{163}{315}\) \(x=\frac{163}{315}:\frac{2}{5}\) \(x=\frac{163}{126}\)