a) 2(3 - 6x) + 8(x - 5) = - 42
=> 6 - 12x + 8x - 40 = -42
=> -34 - 4x = -42
=> 4x = -34 + 42
=> 4x = 8
=> x = 8 : 4
=> x = 2
b) 5x - (3x + 1) = 4 - 1/3 + x
=> 5x - 3x - 1 = 4 - 1/3 + x
=> 2x - 1 = 11/3 + x
=> 2x - x = 11/3 + 1
=> x = 14/3
a) \(2\left(3-6x\right)+8\left(x-5\right)=-42\)
\(\Leftrightarrow6-12x+8x-40=-42\)
\(\Leftrightarrow-4x=-42+40-6\)
\(\Leftrightarrow-4x=-8\)
\(\Leftrightarrow x=2\)
b)\(5x-\left(3x+1\right)=4-\frac{1}{3}+x\)
\(\Leftrightarrow5x-3x-1=4-\frac{1}{3}+x\)
\(\Leftrightarrow5x-3x-x=4-\frac{1}{3}+1\)
\(\Leftrightarrow x=\frac{14}{3}\)
a) 2.(3 - 6x) + 8.(x - 5) = -42
<=> 6 - 12x + 8x - 40 = -42
<=> -4x = -8
<=> x = 2
b) 5x - (3x + 1) = 4 - \(\frac{1}{3}\)+ x
<=> 5x - 3x - 1 - x = \(\frac{12}{3}\) - \(\frac{1}{3}\)
<=> x = \(\frac{11}{3}+1\)
<=> x = \(\frac{11}{3}+\frac{3}{3}\)
<=> x= \(\frac{14}{3}\)
Dấu " <=> " là dấu tương đương nha
a) 2.(3-6x) + 8̣(x-5) =-42
6-12x + 8x-40 = -42
-4x =-42+34
-4x =-8
x =2
b )5x-̣(3x-1) =4-1/3 + x
2x-1 =11/3+x
x =8/3
