a, x2 = 4
x2 = 22
=> x=+2
Vậy x=+2
b, (x - 1)2 = 9
(x - 1)2 = 32
\(\Rightarrow\orbr{\begin{cases}x-1=3\\x-1=-3\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3+1=4\\x=-3+1=-2.\end{cases}}}\)
Vậy x=4 hoặc x=-2
c, (x - 2)3 = -27
(x - 2)3 = (-3)3
x - 2 = -3
x = -3+2
x = -1
Vậy x=-1
d, 3(x + 2)4 = 48
(x + 2)4 = 48:3
(x + 2)4 = 16
(x + 2)4 = 24
\(\Rightarrow\orbr{\begin{cases}x+2=4\\x+2=-4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4-2=2\\x=-4-2=-6\end{cases}}}\)
Vậy x=2 hoặc x=-6
a) x2 = 4
x2 = 22
=> x = 2
vậy x = 2
b) (x - 1)2 = 9
(x - 1)2 = 32
=> x - 1 = 3
=> x = 3 + 1
=> x = 4
vậy x = 4
c) (x - 2)3 = -27
(x - 2)3 = -33
=> x - 2 = -3
=> x = -3 + 2
=> x = -1
vậy x = -1
d) 3 . (x + 2)4 = 48
(x + 2)4 = 48 : 3
(x + 2)4 = 16
(x + 2)4 = 24
=> x + 2 = 2
=> x = 2 - 2
=> x = 0
vậy x = 0
mk ko bt rút ra bài toán TQ mong bn thông cảm nha
k cho mk vs ạ
a) \(x^2=4\Leftrightarrow2^2=4\Leftrightarrow x=2\)
b) \(\left(x-1\right)^2=9\Leftrightarrow3^2=9\Leftrightarrow x-1=3\)
\(x=3+1\)
\(x=4\)
c) \(\left(x-2\right)^3=-27\)
\(\Leftrightarrow\left(-3\right)^3=-27\)
\(\Leftrightarrow x-2=-3\)
\(x=-3+2\)
\(x=-1\)
d) \(3\left(x+2\right)^4=48\)
\(\Leftrightarrow\left(x+2\right)^4=48:3\)
\(\Leftrightarrow\left(x+2\right)^4=16\)
\(\Leftrightarrow2^4=16\Leftrightarrow x+2=2\)
\(x=2-2\)
\(x=0\)
\(#hoktot\)
x^2=2^2
x=2