Question

Tìm x, biết:

a) \(\left|x-1,7\right|=2,3;\)

b) \(\left|x+\frac{3}{4}\right|-\frac{1}{3}=0\)
tl nhanh giùm mik nhé

Answer 1

a)   \(\left|x-1,7\right|=2,3\)

\(\Rightarrow\orbr{\begin{cases}x-1,7=2,3\\x-1,7=-2,3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=4\\x=-0,6\end{cases}}\)

b)   \(\left|x+\frac{3}{4}\right|-\frac{1}{3}=0\)

\(\Rightarrow\left|x+\frac{3}{4}\right|=\frac{1}{3}\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{3}{4}=\frac{1}{3}\\x+\frac{3}{4}=-\frac{1}{3}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-\frac{5}{12}\\x=-\frac{13}{12}\end{cases}}\)