Các câu hỏi tương tự
Tìm x, biết:
a) \(x\left(x-1\right)-x^2+2\text{x}=5\)
b) \(8\left(x-2\right)-2\left(3\text{x}-4\right)=2\)
c) \(\left(3\text{x}+2\right)\left(x-1\right)-3\left(x+1\right)\left(x-2\right)=4\)
d) \(\left(3\text{x}-5\right)\left(7-5\text{x}\right)-\left(5\text{x}+2\right)\left(2-3\text{x}\right)=4\)
Tìm x:
a)\(\text{(x-5)(x+5)-(x+3)^2+3(x-2)^2=(x+1)^2-(x+4)(x-4)+3x^2}\)
\(\text{b)(2x+3)^2}+\left(x-1\right)\left(x+1\right)=5\left(x+2\right)^2-\left(x-5\right)\left(x+1\right)+\left(x+4\right)^2\)
chứng minh rằng biểu thức không thuộc vào biến x:
\(A=\left(3\text{x}-5\right)\left(2\text{x}+11\right)-\left(2\text{x}+3\right)\left(3\text{x}+7\right)\)
Tính:1. frac{x^2}{x^2-x}-frac{x^2}{x+1}-frac{2text{x}}{x^2-1}2. frac{4x^2-3x+5}{x^3-1}-frac{1-2text{x}}{x^2+x+1}-frac{6}{x-1}3. frac{5}{2text{x}^2+6text{x}}-frac{4-3text{x}^2}{x^2-9}-34. frac{7}{8x^2-18}+frac{1}{2text{x}^2+3text{x}}-frac{1}{4text{x}-6}5. frac{1}{xleft(x+1right)}+frac{1}{left(x+1right)left(x+2right)}+...+frac{1}{left(x+9right)left(x+10right)}
Đọc tiếp
Tính:
1. \(\frac{x^2}{x^2-x}-\frac{x^2}{x+1}-\frac{2\text{x}}{x^2-1}\)
2. \(\frac{4x^2-3x+5}{x^3-1}-\frac{1-2\text{x}}{x^2+x+1}-\frac{6}{x-1}\)
3. \(\frac{5}{2\text{x}^2+6\text{x}}-\frac{4-3\text{x}^2}{x^2-9}-3\)
4. \(\frac{7}{8x^2-18}+\frac{1}{2\text{x}^2+3\text{x}}-\frac{1}{4\text{x}-6}\)
5. \(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+...+\frac{1}{\left(x+9\right)\left(x+10\right)}\)
thực hiện phép tính
a, \(4\text{x}.\left(5\text{x}^2-2\text{x}+3\right)\)
b, \(\left(x-2\right).\left(x^2-3\text{x}+5\right)\)
Giải phương trình sau:
\(\left(2\text{x}^2+x-2018\right)^2+4\left(x^2-5\text{x}-2017\right)^2\) = \(4\left(2\text{x}^2+x-2018\right)\left(x^2-5\text{x}-2017\right)\)
Tìm giá trị của biểu thức:
\(\frac{\left(x-2\right)\left(2\text{x}+2\text{x}^2\right)}{\left(x+1\right)\left(4\text{x}-x^3\right)}\)với x=\(\frac{-1}{2}\)
\(\frac{1}{\left(x+y\right)^2}\cdot\left(\frac{1}{x^3}+\frac{1}{y^3}\right)+\frac{3}{\left(x+y\right)^{\text{4}}}\cdot\left(\frac{1}{x^2}+\frac{1}{y^2}\right)+\frac{6}{\left(x+y\right)^5}\cdot\left(\frac{1}{x}+\frac{1}{y}\right)\)
Giúp vs cần gấp
Xác định a,b,c,d thỏa mãn đẳng thức.
a) \(\left(\text{ax+b}\right)\left(x^2+c\text{x+1}\right)=x^3-3\text{x}+2\)
b) \(x^4+\text{ax}^2+b=\left(x^3-3\text{x}+2\right)\left(x^2+c\text{x}+d\right)\)
Mọi người giúp mình nha!