a) (72-x).9=7.(x-40)
648-9x=7x-280
648+280=7x+9x (chuyển vế)
928=16x
x=928:16=58
b) (37-x).7=3.(x+13)
259-7x=3x+39
259-39=3x+7x
220=10x
x=220:10=22
c)(x-1).(x+3)=(x-2).(x+2)
x2+3x-x-3=x2+2x-2x-4
(x2-x2)+(3x-x-2x+2x)=-4+3
0+2x=-1
x=-1/2
Tìm x
a) \(\frac{x+5}{40}+\frac{x+7}{38}+\frac{x+9}{36}=\frac{x+11}{34}+\frac{x+13}{32}-1\)
b) /3x - 2/ - x = 7
c) /2x - 3/ > 5
Tìm x biết
a) x+2x+3x+4x+...+100x=-213
b)\(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
c)3(x-2)+2(x-1)=10
d)\(\frac{x+1}{3}=\frac{x-2}{4}\)
e)\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
f)\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
tìm x
a. \(14\frac{1}{3}\):\(1\frac{1}{3}\)=26:(2x-1)
b.0,2:\(1\frac{1}{5}\)=\(\frac{2}{3}\):(6x+7)
c.\(\frac{37-x}{x+16}\)=\(\frac{3}{7}\)
d.\(\frac{72-x}{7}\)=\(\frac{x-70}{9}\)
\(\frac{x-3}{7-5x}=\frac{1}{6}\)
b) \(\frac{37-x}{x+13}=\frac{3}{7}\)
c) \(\frac{4}{7}=\frac{7}{X^2}\)
Tìm x,y,z
\(a,0,2:1\frac{1}{5}=\frac{2}{3}:\left(6.x+7\right)\)
\(b,\frac{37-x}{x+13}=\frac{3}{2}\)
\(c,\frac{x-2}{x-1}=\frac{x+4}{x+7}\)
\(d,\frac{x}{y}=\frac{2}{3};x.y=96\)
\(e,\frac{x}{2}=\frac{y}{3}=\frac{z}{5};x.y.z=810\)
Ai giúp mình đầu tiên mình k cho nha
Tìm x, biết:
a) \(\frac{x+5}{5}+\frac{x+5}{7}+\frac{x+5}{9}=\frac{x+5}{11}+\frac{x+5}{13}\)
b)\(\frac{x+2}{100}+\frac{x+3}{99}+\frac{x+4}{98}=\frac{x+5}{97}+\frac{x+6}{96}+\frac{x+7}{95}\)
c) (x+2) - (x+3) >0
d)\(\left(x-5\right)\left(x+\frac{7}{3}\right)\ge0\)
Tìm x biết:
a) \(\frac{x+1}{5}=\frac{x+2}{6}\)
b)\(\frac{x+1}{2}=\frac{8}{x+1}\)
c)\(\frac{2x-5}{5}=\frac{20}{2x-5}\)
d)\(\frac{37-x}{x+13}=\frac{3}{7}\)
TÌm số hữu tỉ x trong tỉ lệ thức:
a) 0,4 : x = x : 0,9
b) \(13\frac{1}{3}:1\frac{1}{3}=26:\left(2x-1\right)\)
c) \(0,2:1\frac{1}{5}=\frac{2}{3}:\left(6x+7\right)\)
d) \(\frac{37-x}{x+13}=\frac{3}{7}\)
Tìm x biết
a) (8-5x).(x+2)+4.(x-2).(x+1)+2.(x-2).(x+2)=0
b)\(\left(-\frac{2}{5}+x\right):\frac{7}{9}+\left(-\frac{3}{5}+\frac{5}{6}\right):\frac{7}{9}=0\)
c)\(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=1\frac{2003}{2004}\)
