a)\(5\left(2x-4\right)-3\left(x+1\right)=-2\left(x-9\right)\)
\(10x-20-3x-3=18-2x\)
\(7x-23=18-2x\)
\(7x-23-18+2x=0\)
\(9x-41=0\)
\(\Rightarrow x=\frac{41}{9}\)
b)\(\left|2x-1\right|+1=x\)
\(\Rightarrow\hept{\begin{cases}2x-1+1=x\\1-2x+1=x\end{cases}\Rightarrow}\hept{\begin{cases}2x=x\\2-2x=x\end{cases}\Rightarrow}\hept{\begin{cases}x=0\\x=\frac{2}{3}\left(koTM\right)\end{cases}}\)
một, 10x -20 -3x -3 + 2x -18 = 0
<=> 9x = 41
<=> x = 41/9
b, \(\orbr{\begin{cases}2x-1=x-1\\2x-1=1-x\end{cases}}\) đk th1 (x> hoặc =1/2 ) th2 x <1/2
\(\orbr{\begin{cases}x=0\\x=\frac{2}{3}\end{cases}}\)
vô nghiệm
