(x - 2005) x 2006 = 0
<=> x - 2005 = 0
<=> x = 2005
Vậy x = 2005
\(456+\left(x-357\right)=1362\) \(\left(2345-x\right)-183=2014\)
\(x-357=906\) \(2345-x=2197\)
\(x=1263\) \(x=148\)
\(\left(x-2005\right).2006=0\) Phần sau tương tự thế !
\(x-2005=0\)
\(x=2005\)
\(a,456+\left(x-357\right)=1362\)
\(x-357=1362-456\)
\(x-357=906\)
\(x=1263\)
\(b,\left(2345-x\right)-183=2014\)
\(2345-x=2197\)
\(x=148\)
\(c,\left(x-2005\right)\times2006=0\)
\(x-2005=0\)
\(x=2005\)
\(d,480+45\times4=\left(x+125\right):5+260\)
\(480+180=\left(x+125\right):5+260\)
\(660=\left(x+125\right):5+260\)
\(400=\left(x+125\right):5\)
\(x+125=2000\)
\(x=1875\)
\(e,2005\times\left(x-2006\right)=2005\)
\(x-2006=1\)
\(x=2007\)
\(g,[\left(x+50\right)\times50-50]:50=50\)
\(\left(x+50\right)\times50-50=2500\)
\(\left(x+50\right)\times50=2550\)
\(x+50=51\)
\(x=1\)
a, 456 + (x - 357) = 1362
x - 357 = 1362 - 456
x - 357 = 906
x = 906 + 357 = 1263
b, (2345 - x) - 183 = 2014
2345 - x = 2014 + 183
2345 - x = 2197
x = 2345 - 2197
x = 148
c, (x - 2005) . 2006 = 0
x - 2005 = 0 : 2006
x - 2005 = 0
x = 0 + 2005
x = 2005
d, 480 + 45 . 4 = (x + 125) : 5 + 260
480 + 180= (x + 125) : 5 + 260
660 = (x + 125) : 5 + 260
(x + 125) : 5 = 660 - 260
(x + 125) : 5 = 400
x + 125 = 400 . 5
x + 125 = 2000
x = 2000 - 125
x = 1975
e, 2005 . (x - 2006) = 2005
x - 2006 = 2005 : 2005
x - 2006 = 1
x = 2006 + 1
x = 2007
g, [(x + 50) . 50 - 50] : 50 = 50
(x + 50) . 50 - 50 = 50 . 50
(x + 50) . 50 - 50 = 2500
(x + 50) . 50 = 2500 + 50
(x + 50) . 50 = 2550
x + 50 = 2550 : 50
x + 50 = 51
x = 51 - 50
x = 1
- Thường thì mấy bài tìm x cấp 2 sẽ phải có thêm phần 'Vậy x = ...' nên bạn thêm vào thì tốt hơn :)
- Chú ý viết dấu nhân = . để tránh nhầm lẫn với x.
a) 456 + ( x - 357 ) = 1362
=> x - 357 = 906
=> x = 1263
b) ( 2345 - x ) - 183 = 2014
=> 2345 - x = 2197
=> x = 148
c) ( x - 2005 ) . 2006 = 0
=> x - 2005 = 0
=> x = 2005
d) 480 + 45 . 4 = ( x + 125 ) : 5 + 260
=> 660 = ( x + 125 ) : 5 + 260
=> ( x + 125 ) : 5 + 260 = 660
=> ( x + 125 ) : 5 = 400
=> x + 125 = 2000
=> x = 1975
e) 2005 . ( x - 2006 ) = 2005
=> x - 2006 = 1
=> x = 2007
g) [( x + 50 ) . 50 - 50] : 50 = 50
=> ( x + 50 ) . 50 - 50 = 2500
=> ( x + 50 ) . 50 = 2550
=> x + 50 = 51
=> x = 1
Tìm x, biết:
a) 456 + (x - 357) = 1362
x - 37 = 1362 - 456
x - 37 = 906
x = 906 + 37
x = 943
b) (2345 - x) - 183 = 2014
2345 - x = 2014 + 183
2345 - x = 2197
x = 2345 - 2197
x = 148
c) (x - 2005) x 2006 = 0
x - 2005 = 0 : 2006
x - 2005 = 0
x = 0 + 2005
x = 2005
e) 2005 x (x - 2006) = 2005
x - 2006 = 2005 : 2005
x - 2006 = 0
x = 0 + 2006
x = 2006
d) 480 + 45 x 4 = ( x + 125 ) : 5 + 260
480 + 180 = ( x + 125 ) : 5 + 260
660 = ( x + 125 ) : 5 + 260
660 - 260 = ( x + 125 ) : 5
400 = ( x + 125 ) : 5
400 x 5 = x + 125
2000 = x + 125
2000 - 125 = x
1975 = x
g) [ ( x + 50 ) x 50 - 50 ] : 50 = 50
( x + 50 ) x 50 - 50 = 50 x 50
( x + 50 ) x 50 - 50 = 2500
( x + 50 ) x 50 = 2500 + 50
( x + 50 ) x 50 = 2550
x + 50 = 2550 : 50
x + 50 = 51
x = 51 - 50
x = 1
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