\(4\left(x+1\right)^2+\left(2x-1\right)-8\left(x-1\right)\left(x+1\right)=11\)
\(\Leftrightarrow10x-4x^2=0\)
\(\Leftrightarrow2x\left(5-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\5-2x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{5}{2}\end{cases}}}\)