\(\frac{3}{x-5}=-\frac{4}{x-2}\)
=> 3(x - 2) = -4(x - 5)
=> 3x - 6 = -4x + 20
=> 3x + 4x = 20 + 6
=> 7x = 26
=> x = 26/7
\(\frac{3}{x-5}=\frac{-4}{x-2}\)
=> 3(x-2) = -4 ( x - 5 )
=> 3x - 6 = -4x + 20
=> 7x = 26
=> x = \(\frac{26}{7}\)
Vậy ...
\(\frac{3}{x-5}=-\frac{4}{x-2}\)
=> 3(x - 2) = -4(x - 5)
=> 3x - 6 = -4x + 20
=> 3x + 4x = 20 + 6
=> 7x = 26
=> x = 26/7
\(\frac{3}{x-5}=\frac{-4}{x-2}\)
=> 3(x-2) = -4 ( x - 5 )
=> 3x - 6 = -4x + 20
=> 7x = 26
=> x = \(\frac{26}{7}\)
Vậy ...
Tim x biet : 20 . 2^x + 1 = 10.4^2 + 1
Tim x : ( 4-x:2)^3 - 1 = 2 . (2^3 - 5 : 2^0 )
tim x:-(x-5)+2=4-x
tim x
a, x-5)^4 =( x-5)^6
b,(x +2) ^5 =2^10
c,5^x :5^2 =125
d, (3x - 2^4) .7^3 =2 . 7^4
tim x : x-2/4=5+x/3
Bai 1: Tim so nguyen x biet:
x+(x+1)+(x+2)+...+35=0
Bai 2: Tim GTLN:
a) 8-(x+2)^2=E
b) -|x+2|+10=F
Bai 3: Tim x \(\in\)Z:
a)(2x-4)(x+4)<0
b)(x+5)(3x-12)>0
Bai 11: Cho:
S=1-2+3-4+5-6+...+19-20
a) S co\(⋮\)2; 3; 5 khong?
b) Tim tat ca cac uoc cua S
chi tiet gi minh nha
1.Tim cac chu so x va y de so 1x8y2 chia het cho 36
2.tim cac gia tri nguyen cua n de phan so A=3.n+2/n-1 co gia tri la so nguyen
3.tim cac chu so x y thoa man
(x-2)^2.(x-3)^2=4
4.tim so tu nhien x biet
(x-5):3/100=20.x/100 +5
Tim x:52/5+52/45+52/x.(x+4)=2010/2011
tim x : a, /x+13/ - / x+2/ = 5 . b, /x-4/ - /x-1/= -3
tim x
36: [ 7 x (X-3) + 4 ] =2^4 : 2^3
[(6 X - 39 ) :3 ] x 28 = 5628
720x [41 - (2 X - 5 =2^3 x 5
Tim x biet.
a/x+5+x-7+x-9=x-5+x-2
b/9(2x-3)+5=4(4-1)-8
c/2=-(×-1)^5+34
d/7=-|x-5|+10