\(3-\frac{1-\frac{1}{2}}{1+\frac{1}{x}}=2\frac{2}{3}\)
\(\Leftrightarrow\frac{\frac{1}{2}}{\frac{x+1}{x}}=3-2\frac{2}{3}\)
\(\Leftrightarrow\frac{1}{2}.\frac{x}{x+1}=\frac{1}{3}\)
\(\Leftrightarrow\frac{x}{x+1}=\frac{2}{3}\)
\(\Leftrightarrow3x=2\left(x+1\right)\)
\(\Leftrightarrow3x-2x=2\)
\(\Leftrightarrow x=2\)
Vậy \(S=\left\{2\right\}\)