\(\left(3-\frac{9}{10}-\left|x+2\right|\right):\left(\frac{19}{10}-1-\frac{2}{5}\right)+\frac{4}{5}=1\)
\(\left(\frac{21}{10}-\left|x+2\right|\right):\frac{1}{2}+\frac{4}{5}=1\)
\(\left(\frac{21}{10}-\left|x+2\right|\right):\frac{1}{2}=\frac{1}{5}\)
\(\frac{21}{10}-\left|x+2\right|=\frac{1}{10}\)
=> |x+2| = 2
TH1: x + 2 = 2 => x = 0
TH2: x + 2 = -2 => x = -4
KL:...