\(2x^2-10x-3x-2x^2=26\)
\(2x^2-13x-2x^2=26\)
\(-13x=26\)
\(x=-2\)
\(2x\left(x-5\right)-x\left(3+2x\right)=26\)
\(\Leftrightarrow\left(2x^2-10x\right)-\left(3x+2x^2\right)=26\)
\(\Leftrightarrow-13x=26\)
\(\Leftrightarrow x=-2\)
\(2x^2-10x-3x-2x^2=26\)
\(2x^2-13x-2x^2=26\)
\(-13x=26\)
\(x=-2\)
\(2x\left(x-5\right)-x\left(3+2x\right)=26\)
\(\Leftrightarrow\left(2x^2-10x\right)-\left(3x+2x^2\right)=26\)
\(\Leftrightarrow-13x=26\)
\(\Leftrightarrow x=-2\)
tìm \(x\) biết:
a) \(2x\left(x-5\right)-x\left(3+2x\right)=26\)
b) \(3x\left(1-2x\right)+2\left(3x+7\right)=29\)
Bài 3: Tìm x biết:
a) \(2x\left(x-5\right)-x\left(2x+3\right)=26\)
b) \(\left(3x^2-x+1\right)\left(x-1\right)+x^2\left(4-3x\right)=\frac{5}{2}\)
bài 11 phân tích đa thức thành nhân tử
a,\(x^2-xy+x\) b,\(x^2-2xy-4+y^2\) c,\(x^3-x^2-16x+16\)
bài 12 tìm x biết :
a,\(2x\left(x-5\right)-x\left(3+2x\right)=26\) b,\(2\left(x+5\right)-x^2-5x=0\)
tìm x
\(2x\left(x-5\right)-x\left(3+2x\right)=26\)
Tìm x
\(2x.\left(x-5\right)-x.\left(3+2x\right)=26\)
\(\left(x-7\right).\left(x-5\right)-12.\left(3x-7\right)=15\)
\(4.\left(18-5x\right)-12.\left(3x-7\right)=15.\left(2x-16\right)-6.\left(x+14\right)\)
\(\left(x-1\right).\left(x^2+x+1\right)=x^3-2x\)
TÌm x
\(2x\left(x-5\right)-x\left(3+2x\right)=26\)
Tìm x:
a) 2x(x-5)-x(2x+3)=26
b) \(\left(3y^2-y+1\right)\left(y-1\right)+y^2\left(4-3y\right)=\frac{5}{2}\)
c) \(2x^2+3\left(x-1\right)\left(x+1\right)=5x\left(x+1\right)\)
Rút gọn biểu thức:
\(\frac{1}{2}x^2.\left(6x-3\right)-x.\left(x^2+\frac{1}{2}\right)+\frac{1}{2}.\left(x+4\right)\)
Tìm x, biết:
\(2x.\left(x-5\right)-x\left(3+2x\right)=26\)
Rút gọn biểu thức:
\(\frac{1}{2}x^2.\left(6x-3\right)-x\left(x^2+\frac{1}{2}\right)+\frac{1}{2}\left(x+4\right)\)
Tìm x, biết:
\(2x.\left(x-5\right)-x\left(3+2x\right)=26\)