Question

Tìm x biết:

2^x+1-2^x = 32

( Trả lời đầy đủ nha)

Answer 1

\(2^{x+1}-2^x=32.\)

\(\Leftrightarrow2^x.\left(2-1\right)=32\)

\(\Leftrightarrow2^x.1=2^5\)

\(\Leftrightarrow x=5\)

Answer 2

     \(2^{x+1}-2^x=32\)

\(2^x\cdot2-2^x\cdot1=2^5\)

 \(2^x\cdot\left(2-1\right)=2^5\)

                    \(2^x=2^5\)

                 \(\Rightarrow x=5\)

Answer 3

\(2^{x+1}-2^x=32\)

\(\Leftrightarrow2^x\times2^1-2^x=32\)

\(\Leftrightarrow2^x\times\left(2^1-1\right)=32\)

\(\Leftrightarrow2^x\times1=32\)

\(\Leftrightarrow2^x=32\div1\)

\(\Leftrightarrow2^x=32\)\(\Leftrightarrow2^x=2^5\Rightarrow x=5\)

Vậy x=5

Answer 4

Ta có: \(2^{x+1}-2^x=32\Leftrightarrow2^x\left(2-1\right)=2^5\Leftrightarrow2^x=2^5\Rightarrow x=5\)

Answer 5

 \(2^x.2-2^x=32\)

^{\(2^x\left(2-1\right)=32\)}

\(2^x=32\)

\(x=5\)

Answer 6

2^x+1 -2x=32

2^x.(2-1)=32

2^x .1=32

2^x=32:1

2^x=32

2^x=2^5

=> x=5

Answer 7

2^x+1 - 2^x = 32

<=> 2^x . 2 - 2^x = 32

<=> 2^x ( 2 - 1 ) = 32

<=> 2^x . 1 = 32

<=> 2^x = 2⁵

=> x = 5

Answer 8

thank