Question

Tìm x, biết:
(2x - 1)^2 = 0

Answer 1

\(\left(2x-1\right)^2=0\Leftrightarrow2x-1=0\Leftrightarrow2x=1\Leftrightarrow x=\dfrac{1}{2}\)

Answer 2

(2x−1)2=0

=2x−1=0

=2x=1

=x=12

Answer 3

\(\left(2x-1\right)^2=0\)

\(\Rightarrow\left(2x-1\right)^2=0^2\)

\(\Rightarrow2x-1=0\)

\(2x=1\)

\(\Rightarrow x=2\)