Cách làm
Bài 1: 25 + 3(x - 8) = 106
3(x - 8) = 106 - 25
3(x - 8) = 81
(x - 8) = 81 : 3
(x - 8) = 27
x = 27 + 8
x = 25
Bài 2: 720 : [41 - (2x - 5)] = 23 . 5
720 : [41 - (2x - 5)] = 8 . 5
720 : [41 - (2x - 5)] = 40
[41 - (2x - 5)] = 720 : 40
[41 - (2x - 5)] = 18
(2x - 5) = 41 - 18
(2x - 5) = 23
2x = 23 + 5
2x = 28
x = 28 : 2
x = 14
Tìm x , biết
a, \(3^2\left(x+14\right)-5^2=5.4\)
b, \(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
Ai nhanh minh tick
Help me !
Tìm x thuộc N , biết :
\(720:[41-\left(2x-5\right)]=2^3.5\)
\(720:\left[41-\left(2.x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=^{ }2^3.5\)
\((x-1)^3=125\)
\(2^{x+2}-2^x=96\)
\(\left(2x+1\right)^3=343\)
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)\(16^x< 128^4\)
2. tìm x
a) \(\left(x-1\right)^3=8\)
b) \(7^{2x-6}=49\)
c) \(\left(2x-14\right)^7=128\)
d) \(x^4.x^5=5^3.5^6\)
e) \(\left[3.\left(x+2\right):7\right].4=120\)
Tìm số nguyên x :
\(720:\left[41-\left(2x+5\right)\right]=40\)
Tìm số tự nhiên x , biết
\(2\cdot\left(x-1\right)^2=8\)
\(\left(2x+1\right)^3=125\)
\(\left(x-2\right)^5=243\)
\(5\left(x-4\right)^2-7=13\)
\(221-\left(3x+2\right)^3=96\)
