Question

tìm x biết:12-n chia hết cho 8-n
4n+5 chia hết cho 2n+1

Answer 1

a) Ta có \(\frac{12-n}{8-n}=\frac{8-n+4}{8-n}=1+\frac{4}{8-n}\)

\(12-n⋮8-n\Leftrightarrow4⋮8-n\) 

hay \(8-n\inƯ\left(4\right)=\left\{1;-1;2;-2;4;-4\right\}\)

\(\Rightarrow n\in\left\{7;9;6;10;4;12\right\}\)

b) Ta có \(\frac{4n+5}{2n+1}=\frac{4n+2+3}{2n+1}=2+\frac{3}{2n+1}\)

\(4n+5⋮2n+1\Leftrightarrow3⋮2n+1\)

Answer 2

\(\Rightarrow2n+1\inƯ\left(3\right)=\left\{1;-1;3;-3\right\}\)

\(\Rightarrow n\in\left\{0;-1;1;-2\right\}\)

Mình lỡ bấm gửi trước khi làm xong, bài tiếp theo nè.