Question

Tìm x, biết

1, \(-\frac{3}{2}\left(\frac{4}{5}-\frac{2}{3}\right)+x=4\left(x-\frac{2}{3}\right)\)

2, \(2\left(\frac{3}{2}-x\right)-\frac{1}{3}=7x-\frac{1}{4}\)

3, \(\frac{1}{5}\left(\frac{-3}{5}10\right)+5x=x-\frac{2}{3}\)

4, \(-\frac{3}{2}\left(5-\frac{1}{6}\right)+4\left(x-\frac{1}{2}\right)=1\)

 

 

Answer 1

1)\(-\frac{3}{2}\left(\frac{4}{5}-\frac{2}{3}\right)+x=4\left(x-\frac{2}{3}\right)\)

\(\Leftrightarrow-\frac{3}{2}\cdot\frac{2}{15}+x=4x-\frac{8}{3}\)

\(\Leftrightarrow-\frac{1}{5}+x=4x-\frac{8}{3}\)

\(\Leftrightarrow x-4x=-\frac{8}{3}+\frac{1}{5}\)

\(\Leftrightarrow-3x=-\frac{37}{15}\)

\(\Leftrightarrow x=\frac{37}{45}\)

 

2)\(2\left(\frac{3}{2}-x\right)-\frac{1}{3}=7x-\frac{1}{4}\)

\(\Leftrightarrow3-2x-\frac{1}{3}=7x-\frac{1}{4}\)

\(\Leftrightarrow-2x-7x=-\frac{1}{4}-3+\frac{1}{3}\)

\(\Leftrightarrow-9x=-\frac{35}{12}\)

\(\Leftrightarrow x=\frac{35}{108}\)

 

3)\(\frac{1}{5}\left(-\frac{3}{5}10\right)+5x=x-\frac{2}{3}\)

\(\Leftrightarrow-\frac{6}{5}+5x=x-\frac{2}{3}\)

\(\Leftrightarrow5x-x=-\frac{2}{3}+\frac{6}{5}\)

\(\Leftrightarrow4x=\frac{8}{15}\)

\(\Leftrightarrow x=\frac{2}{15}\)

 

4)\(-\frac{3}{2}\left(5-\frac{1}{6}\right)+4\left(x-\frac{1}{2}\right)=1\)

\(\Leftrightarrow-\frac{15}{2}+\frac{1}{4}+4x-2=1\)

\(\Leftrightarrow4x=1+\frac{15}{2}-\frac{1}{4}+2\)

\(\Leftrightarrow4x=\frac{41}{4}\)

\(\Leftrightarrow x=\frac{41}{16}\)