Question

tìm x , biết

1, 2\(\left(\frac{3}{4}-5x\right)=\frac{4}{5}-3x\)

2, \(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)

3, 3\(\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)

4, a\(\left(\frac{1}{2}-x\right)-5\left(x-\frac{3}{10}\right)=\frac{7}{4}\)

 

Answer 1

1,\(2\left(\frac{3}{4}-5x\right)=\frac{4}{5}-3x\)

\(\frac{6}{4}-10x=\frac{4}{5}-3x\)

\(\frac{6}{4}+\frac{4}{5}=7x\)

\(\frac{23}{10}=7x\)

\(\frac{23}{70}=x\)

2,\(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)

\(\frac{3}{2}-1-4x=\frac{2}{3}-7x\)

\(\frac{3}{2}-1-\frac{2}{3}=-3x\)

\(\frac{-1}{6}=-3x\)

\(\frac{1}{18}=x\)

3,\(3\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)

\(\frac{3}{2}-3x+\frac{1}{3}=\frac{7}{6}-x\)

\(\frac{3}{2}-\frac{7}{6}+\frac{1}{3}=2x\)

\(\frac{2}{3}=2x\)

\(\frac{1}{3}=x\)

4,mình không hiểu a ở đây là gì