x^3+5x^2+8x+4=0
x^3+x^2+4x^2+4x+4x+4=0
x^2(x+1)+4x(x+1)+4(x+1)=0
(x+1)(x^2+4x+4)=0
x+1=0 =>x=-1
x^2+4x+4=0
x^2+2x+2x+4=0
x(x+2)+2(x+2)=0
(x+2)^2=0
x=-2
Vậy x=-2,x=-1
Tìm x,biết
a) x^3-5x^2+8x-4=0
b)x^5-x^3-x^2+1=0
Tìm x biết
a) 4(x-1)×(x+5)-(x+2)×(x+5)=3×(x-1)×(x+2)
b) x^3-5x^2+8x-4=0\
Tìm x, biết
1)x3-5x2+8x-4=0
2)2x3-x2+3x+6=0
Tìm x,biết
a) ( x+2)×(x+3)-(x -2)×(x+5)=0
b) (2x+3)×(x-4)+(x-5)×(x-2)=(3x-5)×(x-4)
c) (8-5x)×(x+2)+4(x-2)×(x+1)+2(x-2)×(x+2)=0
d) (8x-3)×(3x+2)-(4x+7)×(x+4)=(2x+1)×(5x-1)-33
Tìm x biết.
a) 4x^2 - 49 = 0 b) x^2 + 36 = 12x
c) 1/16x^2 - x + 4 = 0 d) x^3 -3√3x2 + 9x - 3√3 = 0
e) (x - 2)^2 - 16 = 0 f) x^2 - 5x - 14 = 0
g) 8x(x - 3) + x - 3 = 0
Tìm x, biết:
6) x^3 - 2x^2 + 2x = 0
7) 2x^3 - 5x^2 + 8x - 5 = 0
tìm x: a)x^4-2x^3+5x^2-10x=0
b)(3x+5)^2=(2x-2)^2
. c)x^3–2x^2+x=0
. d)x^2(x-1)-4x^2+8x-4=0
tìm x
(2x-3)^2-(x+5)^2=0
x*(2x-7)-4x+14=0
x^3-5x^2+8x-4=0
Tìm x biết :
a)\(x^3+5x^2+8x-4=0\)
b) \(\left(x^2+x\right)\left(x^2+x+1\right)=6\)
