Question

tim x biet x^3-3x=0

Answer 1

\(x^3-3x=0\\ \Leftrightarrow x\left(x^2-3\right)=0\\ \orbr{\begin{cases}x=0\\x^2-3=0\end{cases}}\\ \orbr{\begin{cases}x=0\\x^2=3\end{cases}}\\ \orbr{\begin{cases}x=0\\x=+_-\sqrt{3}\end{cases}}\)

Answer 2

x³ - 3x = 0

x.x² - 3x = 0

x.(x² - 3) = 0

=> x = 0 hoặc x² - 3 = 0

=> x = 0 hoặc x² = 3

=> x = 0 hoặc x = \(\sqrt{3}\)

Answer 3

x³-3x=0

=>x(x²-3)=0

=>\(\hept{\begin{cases}x=0\\x^2-3=0\end{cases}=>\orbr{\begin{cases}x=0\\x=+-\sqrt{3}\end{cases}}}\)

Ai k mk mk sẽ k lại

Answer 4

\(x^3-3x=0\)

\(\Leftrightarrow x\left(x^2-3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x^2-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x^2=3\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0\\-1,732..\end{cases}}}\)

~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~
~~~~~~~~~~~~

Answer 5

qiojwfiorgrgj90grjg098j900gu3rg93g8053hg3