x2=2 nhân x
suy ra 2 nhân x +x=0-1
x nhân ( 2+1)=-1
x nhân 3 =-1
x= -1 chia 3
x= -1/3
\(x^2+x+1=0\Leftrightarrow x\left(x+1+1\right)=0\)
\(\Leftrightarrow x=0\)hoặc \(2+x=0\)
\(\Leftrightarrow x=-2\)
Vậy \(x=0\)hoặc \(x=-2\)
x2=2 nhân x
suy ra 2 nhân x +x=0-1
x nhân ( 2+1)=-1
x nhân 3 =-1
x= -1 chia 3
x= -1/3
\(x^2+x+1=0\Leftrightarrow x\left(x+1+1\right)=0\)
\(\Leftrightarrow x=0\)hoặc \(2+x=0\)
\(\Leftrightarrow x=-2\)
Vậy \(x=0\)hoặc \(x=-2\)
a, Cho F(x) = a x+b . Tim a,b biet f(0) = 3 va F(2) =-1
b, Cho F(x) =a x+ b. Tim a,b biet F(1) = -1 va F(-2) = 8
c, Cho F(x) =a x +b .tim a,b biet F(0) = 1 va F(-2) = -9
tim x biet : |x^2+x|+|(x+1)*(x-2)|=0
tim x thuoc Z biet x^3-x^2+x-1=0
tim x biet (x^2-1)(x^2-3)(x^2-5)(x^2-7)<=0
TIM X BIET
(X+1) (X-2) < 0
tim x biet
a) [x-3].[x+2]=0
b) [x+1] . x < 0
tim x biet -3x/4.(1/x+2/7)=0
tim x biet :
( 2-x ) x (4/5-x ) < 0
(x - 3/2) x ( 2x + 1 ) > 0
Tim x,y,z biet:
1)|x|+|1-x|+|x+2|=5
2)|x-1/2|+|y+2\3|+|x^2+xz|=0