xin loi , cau a) la x^2 +3x <0
xin loi , cau a) la x^2 +3x <0
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}vax-2y+3z=14\)
de bai la tim x, y, z biet
giup mk
mk tk
mk dag voi
1,tim ba so x,y,z.bt rang:
x/2=y/3,y/4=z/5(dau / la phan)
2,tim 2 so x,ybt:x:2=y:(-5) va x-y=7
nhanh thi tick
tim gia tri cua x biet !4-!x-3!!=3
luu y:! la gia tri tuyet doi
Cho bieu thuc :
C = ( 1 - 3x ) . x - 2x . ( x - 1 ) + 8
a ) Thu gon C
b ) Tinh gia tri bieu thuc voi x = -3
c ) Tim x de C = 8
d ) Tim ngiem cua C
dau . la dau nhan nha cac bn
nhanh nhanh nha mk dang can gap
\(\frac{x+1}{3}=\frac{y+2}{-4}=\frac{z-3}{5}va3x+2y+4z=47\)
tim x, y, z biet
mk tk
mk gap
giup mk
tìm x biết :
a) |x-1/3| +1/2 = 1
b) |x+2|+|x-2|=0
c) |x-1/4|+x=1/3
ai nhanh nhất mk sẽ tk !
1) Tim x, biet:
a) /2-x / =1/2
b) 3- / x +1/2 / = 1
c) / x - 1/2 / < 3
d) / x + 2 / > 1
tat ca deu la bai lien quan den gia tri tuyet doi nha may ban
giup mk nha
cau 1:tinh gia tri bieu thuc
3/4 +1/1/4 *2/2/3-(-1/2)^2:6/5
cho ma co 2 dau/la hon so,con 1 dau la phan so,con ^2 la mu 2
cau 2:tim x biet
( x-1)^5= -32
cho ^5 co nghia la mu 5
Tim x,y,z biet:
1)|x|+|1-x|+|x+2|=5
2)|x-1/2|+|y+2\3|+|x^2+xz|=0