\(\left(x^2\right)^2=\frac{81}{16}\)
\(x^4=\frac{3^4}{2^4}\)
\(x^4=\left(\frac{3}{2}\right)^4\)
\(\Rightarrow x=\frac{3}{2}\)hoặc \(x=-\frac{3}{2}\)
Tìm x
\(\left(\frac{2}{3}\right)^x=\frac{16}{81}\)
Tìm x biết
a)\(\left(-\frac{1}{3}\right)^3.x=\frac{1}{81}\) b) \(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\) c) \(\left(x+\frac{1}{2}\right)^4=\frac{16}{81}\)
Tìm x biết
a) \(\left(\frac{3}{5}\right)^5.x=\left(\frac{3}{7}\right)^7\)
b) \(\left(-\frac{1}{3}\right)^3.x=\frac{1}{81}\)
c) \(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
d) \(\left(x+\frac{1}{4}\right)^4=\frac{16}{81}\)
Ai xong nhanh nhất cho 1 like \(☺\)
Tìm x:
\(\left(x+\frac{1}{2^{ }}\right)4\)\(=\frac{16}{81}\)
nhanh+đúng=2 tick
tìm x biết:
(x + \(\frac{3}{4}\) )2=\(\frac{49}{16}\)
9\(^{3x+1}\)=9\(^{x+13}\)
(3x-1)2 =81
Tìm x biết:
a,(2/3)^x+1=16^81
b,(x+2/5)^5=(x+2/5)^3
Bài 1:tìm x
a) \(\frac{64}{4^{\left(X+1\right)}}=4\)
b) \(-\frac{4}{9}+\left|5x+\frac{1}{2}\right|=\sqrt{\frac{16}{81}}\)
Viết số \(\frac{16}{81}\) dưới dạng lũy thừa.Ví dụ : \(\frac{16}{81}\) = \(\left(\frac{4}{9}\right)^2\).Hãy tìm một cách viết khác!!!
tìm x biết : a,\(\frac{x^7}{81}=27\); b,\(\frac{x^8}{9}=729\); c.\(^{\left[x-\frac{1}{2}\right]^0}\); d,\(\left[X-2\right]^2=1\); e, \(\left[2X-1\right]^3=8\); f,\(\left[X+\frac{1}{2}\right]^2\)=\(\frac{1}{16}\)
