\(x^2-3x=\left(x-2\right)\left(3-x\right)\\ x\left(x-3\right)-\left(x-2\right)\left(3-x\right)=0\\ x\left(x-3\right)+\left(x-2\right)\left(x-3\right)=0\\ \left(x-3\right)\left(x+x-2\right)\\ \left(x-3\right)\left(2x-2\right)=0\\ 2\left(x-3\right)\left(x-1\right)=0\\ \left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)