Question

Tìm x biết :

(x+1)+(x+3)+....+(x+99)=4900

Answer 1

\(\left(x+1\right)+\left(x+3\right)+...+\left(x+99\right)\text{=}4900\)

\(x+1+x+3+...+x+99\text{=}4900\)

\(49x+4900\text{=}4900\)

\(49x\text{=}0\)

\(x\text{=}0\)

Answer 2

\(\left(x+1\right)+\left(x+3\right)+...+\left(x+99\right)=4900\)

\(\Rightarrow\left(x+x+...+x\right)+\left(1+3+...+99\right)=4900\)

\(\Rightarrow50x+2500=4900\)

\(\Rightarrow50x=2400\)

\(\Rightarrow x=48\)

Vậy x = 48.