Question

Tìm x biết  (x+1)+(x+3)+(x+5)+....+(x+99)=0

Answer 1

(99-1):2+1)x(99+1):2=2500

(0-2500):50 = -50

vậy x = -50

Answer 2

(x+1)+(x+3)+(x+5)+...+(x+99) = 0

x+x+x+...+x+(1+3+5+...+99) = 0

50x + 2500 = 0

=> 5x = 0 - 2500 = -2500

=> x = -2500 : 5

=> x = -500

Answer 3

Tìm x biết  

(x+1)+(x+3)+(x+5)+....+(x+99)=0

\(\Rightarrow\) x+1+x+3+x+5+....+x+99=0

\(\Rightarrow\)x + ( 1+3+5+...+99 ) = 0

\(\Rightarrow\)x + 2500 = 0

\(\Rightarrow\)x            = 0 - 2500

\(\Rightarrow\)x           = -2500

Answer 4

(x+1)+(x+3)+(x+5)+.....+(x+99)=0

x+x+x+...+x+(1+3+5+..+99)=0

50x+2500=0

50x=0 trừ 2500=âm 2500

x=âm 2500:50

x=âm 50

Answer 5

=> 50 x +(1+3+5+..+99) = 0

=> 50 x +2500 = 0

=> 50 x = -2500

=> x = -50

Answer 6

Ta có : ( x + 1 ) + ( x + 3 ) + ( x + 5 ) + ... + ( x + 99 ) = 0 

<=> ( x + x + x + ... + x ) + ( 1 + 3 + 5 + ... + 99 )  = 0

<=> 50 .x                       + 2500                               = 0

<=>            50 .x                                                         = -2500

<=>            x                                                                = -50 

Vậy x = -50

Answer 7

=>x=-50