Question

Tim x biet 

(x+1)^2=4/9

Answer 1

(x + 1)² = \(\frac{4}{9}\)

=> x + 1 = \(\frac{2}{3}\)hoặc x + 1 = \(-\frac{2}{3}\)

=> x = \(\frac{-1}{3}\) hoặc x = \(-\frac{5}{3}\)

Answer 2

\(\left(x+1\right)^2=\frac{4}{9}\Rightarrow\left(x+1\right)^2=\left(+-\frac{2}{3}\right)\)

\(\Rightarrow x+1=\frac{2}{3}\) hoac \(x+1=-\frac{2}{3}\Rightarrow x=-\frac{1}{3}\) hoac \(x=-\frac{5}{3}\)

Answer 3

(x + 1)² = 4/9

=> x + 1 = \(\sqrt{\frac{4}{9}}=\frac{2}{3}\)  và x + 1 = -2/3

=> x + 1 = 2/3 => x = 2/3  - 1 = -1/3

=> x  + 1  = -2/3  => x = -2/3 - 1 = -5/3