Tìm x biết \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
a) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\Leftrightarrow\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
\(\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
\(\Leftrightarrow x-23=0\)( vì \(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\ne0\))
\(\Leftrightarrow x=23\)
Vậy nghiệm của pt x=23
\(\dfrac{x-23}{24}\)+\(\dfrac{x-23}{25}\)=\(\dfrac{x-23}{26}\)+\(\dfrac{x-23}{27}\)
Giải phương trình x - 2 3 - x - 2 4 + x - 2 5 = 0
tìm x biết
\(\frac{\left(24-x\right)^2+\left(24-x\right)\left(x-25\right)+\left(x-25\right)^2}{\left(24-x\right)^2-\left(24-x\right)\left(x-25\right)+\left(x-25\right)^2}=\frac{19}{49}\)
giải phương trình sau:
\(x = {x-25 \over 25} + {x-26 \over 24} + {x-27 \over 23} + {x-26 \over 22} +{x-17 \over 30}\)
giup minh phan tich da thuc thanh nhan tu
1)x^2+4x+3
2)x^2-4x+3
3)x^2-x-5
4)x^2+4x-5
5)-x^2-x+6
6)x^2+7x+10
7)-x^2-3x+10
8)x^2+7x+12
9)x^2+4x+3
10)(x^2-2x+63)
11)x^2+10x+24
12)-x^2-4x+21
13)2x^2+11x+12
14)x^2-x+30
15)x^2+11x+30
16)2x^2+5x-12
17)x^2-5x-14
18)2x^2+9x+9
19)x^2+x-72
20)-2x^2-15x+27
21)x^2-x-12
22)-x^2+x+15
23)-x^2+5x+14
24)x^2-7x-18
lam on !!!!!!!!!!!!!!!!!!!!!!!.....!
\(\frac{x+22}{1996}+\frac{x+23}{1995}+\frac{x+24}{1994}+\frac{x+25}{1993}=4\)
Ai giups mik v