=> 100x+[(100+1).100:2]=5750
=> 100x+10100:2=5750
=> 100x=5750-5050
=> x=700:100
=> x=7
(x+1)+(x+2)+(x+3)+........+(x+100)=5750
(x+x+...+x)+(1+2+3+...+100)=5750
(x.100)+(1+100).100:2=5750
(x.100)+5050=5750
x.100=5750-5050
x.100=700
x =700:100
x = 7
Vậy x=7
x+1+X+2+X+3+...+X+100=5750
100.x +(1+2+3+..+100)=5750
100.x +5550=5750
100.x =200
x=2
Ta có: ( x+1) + (x+2) + (x+3) +...+ ( x+100) = 5750
<=> ( x + x + x + ...... + x ) + (1 + 2 + 3 + ..... + 100) = 5750
<=> 100x + 5050 = 5750
=> 100x = 5750 - 5050
=> 100x = 700
=> x = 700 : 100
=> x = 7