Tim x biet
a) 25,4 - \(\frac{1}{4}\): x + 1250%=37,5
b) \(3\frac{1}{8}\):(\(\frac{2}{5}\)- x) nhan \(\frac{8}{25}\)=3
so sanh hai phan so sau :
\(\frac{x-1}{3}\) va \(\frac{x+1}{3}\)
biet x > 1
Tim x
x*\(\frac{5}{2}\)-x*\(\frac{3}{4}\)=\(\frac{11}{56}\)
B) Tim phan so \(\frac{a}{b}\)
\(\frac{a}{b}\)*\(\frac{2}{5}\)+\(\frac{1}{5}\)*\(\frac{a}{b}\)=\(\frac{1}{12}\)+\(\frac{1}{4}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)\(1\). Tìm x
Tìm x: \(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
Tìm x biết: \(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
(x+\(\frac{1}{2}\)) + ( x+\(\frac{1}{4}\)) + (x+\(\frac{1}{8}\)) + (x+\(\frac{1}{16}\)) = 1
Tìm x;
(\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)) : x = (\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+.......+\frac{1}{132}\))
tìm x biết: \(\frac{\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)}{x}=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{132}\)