Lời giải:
$x-\frac{1}{3}+x-\frac{1}{5}+x-\frac{1}{7}+x-\frac{1}{9}=0$
$(x+x+x+x)-(\frac{1}{3}+\\frac{1}{5}+\frac{1}{7}+\frac{1}{9})=0$
$4\times x-\frac{248}{315}=0$
$4x=\frac{248}{315}$
$x=\frac{248}{315}:4=\frac{62}{315}$
Lời giải:
$x-\frac{1}{3}+x-\frac{1}{5}+x-\frac{1}{7}+x-\frac{1}{9}=0$
$(x+x+x+x)-(\frac{1}{3}+\\frac{1}{5}+\frac{1}{7}+\frac{1}{9})=0$
$4\times x-\frac{248}{315}=0$
$4x=\frac{248}{315}$
$x=\frac{248}{315}:4=\frac{62}{315}$
tìm x, biết: \(\frac{x-1}{5}+\frac{x-1}{7}+\frac{x-1}{9}+....+\frac{x-1}{35}+\frac{x-1}{37}=0\)
A = $\frac{1}{1 x 3}$ + $\frac{1}{5 x 7}$ + $\frac{1}{9 x 11}$ +....+ $\frac{1}{2021 x 2023}$ + $\frac{1}{2025 x 2027}$
bài 1: tìm x:
a) \(x\cdot\frac{7}{9}=\frac{2}{3}+2\frac{1}{2}\) b) \(\frac{5}{7}+x:\frac{9}{4}=\frac{4}{3}\)
Tìm x biết:
\(1-\left(5\frac{4}{9}+x-7\frac{7}{18}\right)\div15\frac{3}{4}=0\)
Tìm \(x\) biết: \(\left(\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+...+\frac{1}{19\cdot21}\right)\cdot x=\frac{9}{7}\)
Bài 1:Tìm x,biết:
a)(1,5*1,9-x-0,5):0,25=7,5:0,125
b)1-\(\left(5\frac{2}{9}+x-7\frac{7}{18}\right)\):2\(\frac{1}{6}\)=0
c)35*\(\left(2\frac{1}{5}-x\right)\)=32
d)\(\frac{4}{3}\)+\(\left(x:2\frac{2}{3}-0,5\right)\)*1\(\frac{35}{55}\)=0,6
e)1\(\frac{1}{3}\)*2\(\frac{2}{4}:\frac{5}{6}\)*1\(\frac{1}{11}\)=11-5:x
Mình cần gấp lắm!Ai nhanh nhất mik tik nha!
\(1-\left[5\frac{4}{9}+x-7\frac{7}{18}\right]:15\frac{3}{4}=0\)
TÌM X NHA
\(A=\left(6:\frac{3}{5}-1\frac{1}{6}x\frac{6}{7}\right):\left(4\frac{1}{5}x\frac{10}{11}+5\frac{2}{11}\right)\)\(B=\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{4}\right)x.......x\left(1-\frac{1}{2015}\right)x\left(1-\frac{1}{2016}\right)\)
\(C=5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}x4\frac{1}{2}-2x2\frac{1}{3}\right):\frac{7}{4}\)
tinh bằng cách thuật tiện nhất
\(\frac{1}{10}x\frac{2}{9}x\frac{3}{8}x\frac{4}{7}x\frac{5}{6}x\frac{6}{5}x\frac{7}{4}x\frac{8}{3}x\frac{9}{2}\)