\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
\(\left(x-\frac{1}{2}\right)^3=\left(\frac{1^3}{3^3}\right)\)
\(\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
=>x-\(\frac{1}{2}=\frac{1}{3}\)
x=\(\frac{1}{3}+\frac{1}{2}=\frac{2}{6}+\frac{3}{6}=\frac{5}{6}\)
x- 1/2^3 = 1/27
x - 1/8 = 1/27
x = 1/27 + 1/8
x = 35/216