Question

tìm x ,biết :

( x +\(\dfrac{1}{10}\) )  x\(\dfrac{5}{6}\) = 3-\(\dfrac{7}{6}\)

Answer 1

\(\left(x+\dfrac{1}{10}\right).\dfrac{5}{6}=\dfrac{18-7}{6}\\ x+\dfrac{1}{10}=\dfrac{11}{6}:\dfrac{5}{6}\\ x+\dfrac{1}{10}=\dfrac{11}{5}\\ x=\dfrac{11}{5}-\dfrac{1}{10}\\ x=\dfrac{22-1}{10}\\x=\dfrac{21}{10}\)

Answer 2

`(x+1/10) xx 5/6 = 3 -7/6`

`(x+1/10) xx 5/6 =18/6 - 7/6`

`(x+1/10) xx 5/6 = 11/6`

`x+1/10 = 11/6 : 5/6`

`x+1/10 = 11/6 xx 6/5`

`x+1/10 = 11/5`

`x=11/5-1/10`

`x=22/10-1/10`

`x=21/10`

Answer 3

\(\left(x+\dfrac{1}{10}\right)\times\dfrac{5}{6}=3-\dfrac{7}{6}\)

\(\left(x+\dfrac{1}{10}\right)\times\dfrac{5}{6}=\dfrac{11}{6}\)

\(x+\dfrac{1}{10}=\dfrac{11}{6}:\dfrac{5}{6}\)

\(x+\dfrac{1}{10}=\dfrac{11}{5}\)

\(x=\dfrac{11}{5}-\dfrac{1}{10}\)

\(x=\dfrac{21}{10}\)