=> ( x-2001/2 + ) + ( x-2002/3 + 1 ) = ( x-2003/4 + 1 ) + ( x-2004/5 + 1 )
=> x-1999/2 + x-1999/3 = x-1999/4 + x-1999/5
=> x-1999/2 + x-1999/3 - x-1999/4 - x-1999/5 = 0
=> (x-1999).(1/2+1/3-1/4-1/5) = 0
=> x-1999=0 ( vì 1/2+1/3-1/4-1/5 > 0 )
=> x = 1999
Vậy x = 1999
Tk mk nha
\(\frac{x-5}{2000}+\frac{x-4}{2001}+\frac{x-3}{2002}=\frac{x-2}{2003}+\frac{x-1}{2004}+\frac{x}{2005}\)
(2001/2002 +2002/2003 + 2003/2004) x(1/3 - 1/4 - 1/12)
Tìm x biết Ax + B = C
A = 158 x 12 - 12/7 - 12/289 -12/85 // 4 - 4/7 - 4/289 - 4/85 : 1/6 x 505505505 / 711711711 - 2005
B = 2003 x [2004 ^2003 + 2004^2002 + ..... + 2004 + 1] - 2004^2004 - 5
C= 2003 x 1986 + 2002 x 17 + 2020 / 2003 x 2004 - 2003 ^2
jup mik nhe
a)1-2-3+4+5-6-7+......+2001-2002-2003+2004
b) (x-1) (x-10).x =0
c) x +8x = 189
Tìm x biết :
(x+4)/2000 +(x+3)/2001 = (x+2)/2002 +(x+1)/2003
Tìm x biết
\(\frac{x+1}{2004}+\frac{x+2}{2003}+\frac{x+3}{2002}+35=2^5\)
Tìm x biết :
\(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)
rút gọn phân số
a/ 2002 x 2003 - 998 / 2003 * 2001 +1010
b/ (-2)^3 x 3^3 x 5 ^ 3 x 7 x 8/3 x 2^4 x 5^3 x 14
Tìm x E N biết \(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)
