(x+1)+(x+3)+(x+5)+......+(x+99) = 2550
(x+x+x+....+x)+(1+3+5+....+99) = 2550
50x + 2500 = 2550
50x = 2550 - 2500
50x = 50
x = 50 : 50
x = 1
(x + 1) + (x + 3) + (x + 5) + ... + (x + 99) = 2550
=> (x + x + x + ... + x) + (1 + 3 + 5 + ... + 99) = 2550
có 50 số x có 50 SH
=> 50x + [(1 + 99) . 50 : 2] = 2550
=> 50x + [100 . 50 : 2] = 2550
=> 50x + [5000 : 2] = 2550
=> 50x + 2500 = 2550
=> 50x = 2550 - 2500
=> 50x = 50
=> x = 50 : 50
=> x = 1
Vậy x = 1