\(x-\frac{1}{3}+3x-\frac{5}{2}+\frac{2x}{9}+\frac{3}{9}=\frac{210}{420}\)
\(x.\left(1+3-5\right)-\left(\frac{1}{3}-\frac{2x}{9}+\frac{3}{9}\right)-\frac{5}{2}=\frac{1}{2}\)
\(-x-\frac{2}{3}+\frac{2x}{9}=\frac{1}{2}+\frac{5}{2}\)
\(-x-\frac{2}{3}+\frac{2x}{9}=3\)
\(-x-\frac{2x}{9}=3+\frac{2}{3}\)
\(-x-\frac{2x}{9}=6\)
\(\frac{-9x}{9}+\frac{-2x}{9}=6\)
\(\frac{-11x}{9}=6\)
\(-11x=6.9\)
\(-11x=54\)
\(x=54\div\left(-11\right)\)
\(x=\frac{-54}{11}\)
vậy \(x=\frac{-54}{11}\)