Các câu hỏi tương tự
tìm x biết : \(\left(\frac{4}{5}\right)^{2x+7}=\frac{625}{256}\)
Tìm x biết :
\(\left(\frac{4}{5}\right)^{2x+7}=\frac{625}{256}\)
tìm x
\(\left(\frac{4}{5}\right)^{2x+7}=\frac{256}{625}\)
Tìm x, biết:
a) \(\left(\frac{4}{5}\right)^{2x+7}=\frac{625}{256}\)
b) \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^x+5^{2x+1}+5^{2x+2}}{132}\)
\(\left(\frac{4}{5}\right)^{2x}+6=\frac{256}{625}\). Tìm x?
Tìm x
\(2^{3x+2}=4^{x+5}\)
\(3^{x+1}=9^x\)
\(\left(\frac{4}{5}\right)^{2x+7}=\frac{625}{256}\)
Mik đang cần gấp
Tìm x biếta,left(frac{4}{5}right)^{2x+7}text{}frac{625}{256}b,frac{7^{x+2}+7^{x+1}+7^x}{57}text{}frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}c,left(4x-3right)^4text{}left(4x-3right)^2d,frac{2x+3}{5x+2}text{}frac{4x+5}{10x+2}e,frac{3x-1}{40-5x}text{}frac{2x-3x}{5x-34}f,frac{15}{x-9}text{}frac{20}{y-12}text{}frac{40}{z-2x} và xytext{}1200
Đọc tiếp
Tìm x biết
a,\(\left(\frac{4}{5}\right)^{2x+7}\text{=}\frac{625}{256}\)
b,\(\frac{7^{x+2}+7^{x+1}+7^x}{57}\text{=}\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
c,\(\left(4x-3\right)^4\text{=}\left(4x-3\right)^2\)
d,\(\frac{2x+3}{5x+2}\text{=}\frac{4x+5}{10x+2}\)
e,\(\frac{3x-1}{40-5x}\text{=}\frac{2x-3x}{5x-34}\)
f,\(\frac{15}{x-9}\text{=}\frac{20}{y-12}\text{=}\frac{40}{z-2x}\) và \(xy\text{=}1200\)
1. Tìm x:
\(\left(\frac{4}{5}\right)^{2x+7}=\frac{625}{256}\)
2. So sánh:
\(a=15^{120}:25^{60}\)và \(b=2^{45}.2^{15}.4^{60}\)
\(\left(\frac{1}{3}\right)^{x+1}=\left(\frac{1}{3}\right)^x\)
\(\left(\frac{4}{5}\right)^x=\frac{256}{625}\)