3x/7+1=-1/8.(-4)
3x/7+1=1/2
3x/7=1/2-1
3x/7=-1/2
suy ra ko có giá trị nào thỏa mãn x
(3x/7+1):(-4)=-1/8
suy ra 3x/7+1=-1/8.(-4)
suy ra 3x/7+1=1/2
suy ra 3x/7=-1/2
suy ra 3x=-1/2.7
suy ra 3x=-7/2
suy ra x=-7/2:3
suy ra x=-7/6
vay x=-7/6
3x/7+1=-1/8.(-4)
3x/7+1=1/2
3x/7=1/2-1
3x/7=-1/2
suy ra ko có giá trị nào thỏa mãn x
(3x/7+1):(-4)=-1/8
suy ra 3x/7+1=-1/8.(-4)
suy ra 3x/7+1=1/2
suy ra 3x/7=-1/2
suy ra 3x=-1/2.7
suy ra 3x=-7/2
suy ra x=-7/2:3
suy ra x=-7/6
vay x=-7/6
Tìm x,y biết :
\(a,\)\(-\frac{1}{2}\)\(\left(3-2x\right)\)\(-7=5-\frac{1}{3}\left(x-\frac{4}{5}\right)\)
\(b,\left(5-\frac{3x}{2}\right):-1\frac{3}{8}=-7\frac{1}{3}\)
\(c,\left(2+3x\right)^2+\left|3x+2y\right|=0\)
Tìm x biết:
a)\(\frac{2}{3}.\left(x-\frac{3}{8}\right)-x-\left(-\frac{7}{8}+\frac{2}{3}\right)=\left(\frac{-3}{4}\right)^3:1\frac{11}{16}\)
b)\(-\frac{7}{8}+\frac{7}{8}:\left(\frac{2}{3}-x\right)+\frac{5}{6}:\left(-1\frac{11}{35}\right)=\left(0,8\right)^2\)
Bài 1:tính giá trị biểu thức sau:
\(B=\left(1-\frac{1}{21}\right).\left(1-\frac{1}{28}\right).\left(1-\frac{1}{36}\right)...\left(1-\frac{1}{1326}\right)\)
Bài 2 tìm x biết
\(a,1\frac{1}{30}:\left(24\frac{1}{6}-24\frac{1}{5}\right)-\frac{1\frac{1}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=\left(-1\frac{1}{15}\right):\left(8\frac{1}{5}-8\frac{1}{3}\right)\)
\(b,\left|3x-\frac{2}{5}\right|=\frac{1}{35}+\left|\frac{-3}{7}\right|\)
\(c,-3\frac{1}{2}-\left(2x+\frac{1}{2}\right):\left(-\frac{3}{7}\right)=0\)
\(d,\left(x-4\right).\left(x+2\right)\le0\)với x thuộc z
giúp mk với
Tìm x biết:\(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
Tìm x biết:
\(\left(2x+\frac{1}{3}\right)\left(\frac{3}{4}x-6\right)-\left(3x-\frac{2}{3}\right)\left(\frac{1}{2}x-\frac{6}{9}\right)=1\)
Bài 15: Tìm x biết:
a, \(-\frac{3}{5}\times x=\frac{1}{4}+0,75\)
b, \(\left(\frac{1}{7}-\frac{1}{3}\right)\times x=\frac{28}{3}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)
c, \(\frac{5}{7}\times x=\frac{9}{8}-0,125\)
d, \(\left(\frac{2}{11}+\frac{1}{3}\right)\times x=\left(\frac{1}{7}-\frac{1}{8}\right)\times36\)
Tìm x
\(\frac{5}{2}-\left(\frac{3}{2}-2\frac{1}{3}+x\right)=\frac{8}{15}-\left(\frac{1}{4}-\frac{7}{10}\right)\)
\(1\frac{2}{3}-1\frac{3}{5}+x=\frac{2}{5}-\left|\frac{3}{4}-\frac{7}{8}\right|\)
\(2-\left(\frac{2}{3}-3\frac{1}{4}+x\right)=1\left|\frac{1}{6}-\frac{13}{12}\right|\)
Tìm x biết \(1\frac{1}{30}:\left(24\frac{1}{6}-24\frac{1}{5}\right)-\left(1\frac{1}{2}-\frac{3}{4}\right):\left(4x-\frac{1}{2}\right)=\left(-1\frac{1}{15}\right):\left(8\frac{1}{5}-8\frac{1}{3}\right)\)
Tìm x, biết:
\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\left(x\notin-2;-5;-10;-17\right)\)
\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=-\frac{3}{4}\)
Với \(x\notin1;3;8;20\)
\(\frac{x+1}{10}+\frac{2+1}{11}\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)