Question

TÌM X BIẾT : 

\(\left(\frac{2}{3}\cdot x-\frac{4}{9}\right)\cdot\left(\frac{1}{2}+\frac{-3}{7}:x\right)=0\)

LÀM NHANH SẼ LIKE NHIỀU ( CẦN RẤT GẤP )

 

Answer 1

\(\frac{6}{7}\)

Answer 2

(2/3x-4/9).(1/2+ -3/7x)=0

=> 2/3x-4/9=0=>2/3x=4/9=>x=2/3=>1/2+ -3/7x=0=>-3/7x=-1/2=>x=7/6

tk cho mk thật nhiều nhé

Answer 3

\(\left(\frac{2}{3}.x-\frac{4}{9}\right).\left(\frac{1}{2}+\frac{-3}{7}.x\right)=0\)

\(\Rightarrow\left(\frac{2}{3}x-\frac{4}{9}\right).\left(\frac{1}{2}+\frac{-3}{7}x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}\frac{2}{3}x-\frac{4}{9}=0\\\frac{1}{2}+\frac{-3}{7}x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}\frac{2}{3}x=\frac{4}{9}\\\frac{-3}{7}x=\frac{1}{2}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{4}{9}:\frac{2}{3}\\x=\frac{1}{2}:\left(\frac{-3}{7}\right)\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{2}{3}\\x=\frac{-7}{6}\end{cases}}\)

Vậy \(x=\frac{2}{3}\)hoặc \(x=\frac{-7}{6}\)