Bài 17: Tìm x \(\in\)Z biết:
\(\frac{2}{3}\times\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\le\frac{x}{18}\le\frac{7}{3}\times\left(\frac{1}{2}-\frac{1}{6}\right)\)
\(1,5+1\frac{1}{4}\times x=\frac{2}{3}\)
Tìm x:\(\left(2,7.x-1\frac{1}{2}.x\right)\div\frac{2}{7}=\frac{-21}{4}\)
\(3\frac{1}{3}\times x+16\frac{3}{4}=-13,25\)
\(\left(4,5-2\times x\right)\div\frac{3}{4}=1\frac{1}{3}\)
tìm x:
\(\left|x\right|-5\frac{3}{7}\times\left|x\right|-\frac{3}{4}=2\times\left|x\right|+\frac{-15}{2}\)
\(50\%+\frac{2}{3}x=x+4\)
\(0,5x-\frac{2}{3}\left(x+1\right)=\frac{-1}{12}\)
\(\frac{1}{2}\left(x-\frac{2}{3}\right)-\frac{2}{5}\left(2-x\right)=\frac{1}{9}\)
Bài 15: Tìm x biết:
a, \(-\frac{3}{5}\times x=\frac{1}{4}+0,75\)
b, \(\left(\frac{1}{7}-\frac{1}{3}\right)\times x=\frac{28}{3}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)
c, \(\frac{5}{7}\times x=\frac{9}{8}-0,125\)
d, \(\left(\frac{2}{11}+\frac{1}{3}\right)\times x=\left(\frac{1}{7}-\frac{1}{8}\right)\times36\)
bài 1 : tìm x biết
a, \(\frac{2}{3}\times\left(x-\frac{5}{6}\right)+\frac{1}{4}=\frac{22}{9}\)
b, \(\frac{2}{3}:\frac{x}{5}=\frac{10}{21}\)
c, \(\frac{7}{3}:\frac{x}{5}=\frac{14}{15}\)
d, \(1-\left(5\frac{4}{9}\times x-7\frac{7}{18}\right):15\frac{3}{4}=0\)
bài 2 : tính gtri bt
a,\(\frac{8}{7}+\frac{1}{5}\times\frac{10}{9}\)
b, \(\frac{3}{2}+\left(\frac{9}{2}+\frac{2}{9}\right)\times\left(\frac{4}{3}-\frac{5}{4}\right)\)
!_ove
1. tìm x biết:
a, \(\left(\frac{2}{3}+x\right)\frac{1}{2}-\frac{1}{3}x=\frac{5}{4}\)
b,\(\left|x+\frac{1}{2}\right|+\frac{1}{2}=\left|\frac{2}{3}-\frac{5}{4}\right|\)
c,\(\left(x+\frac{2}{3}\right)^2.\frac{1}{2}=1\frac{1}{2}\)
Tìm x thuộc Z, biết:
\(\frac{4}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)
Tìm x biết:
a) \(-4\frac{3}{5}.2\frac{4}{23}
\(\text{Tìm }x,\text{ }\text{biết:}\)
\(1\text{)}\text{ }2.\left(x-\frac{1}{3}\right)-3\left(x-\frac{1}{2}\right)=\frac{1}{2}x\)
\(2\text{) }-3\left(x-\frac{1}{4}\right)-\frac{1}{3}\left(x+\frac{1}{2}\right)=x\)
\(\text{3) }\frac{3}{2}\left(x-\frac{5}{3}\right)-\frac{4}{5}=x+1\)
\(\text{4) }\frac{1}{6}\left(2.x-3\right)=\frac{1}{2}\left(-x+\frac{1}{4}-\frac{2}{3}\right)\)
\(\text{5) }-\frac{2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2.x-1\right)\)