đó là TH1..
TH2 :(1-2x)^2=9
=> (1-2x)^2=(-3)^2
=> 1-2x=-3
=> 2x= 4
=> x=2
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tim x , y
a ,\(\left(3x-5\right)^{10}\)+ |2y - x | = 0
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Tìm x biết:
\(\left(2x+\frac{1}{3}\right)\left(\frac{3}{4}x-6\right)-\left(3x-\frac{2}{3}\right)\left(\frac{1}{2}x-\frac{6}{9}\right)=1\)
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Tìm x, biết:
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tim x
Tìm x liên quan đến lũy thừa:
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27 tháng 8 2023 lúc 20:19
Tìm x:
a) \(\dfrac{1}{3}.x+\dfrac{2}{5}\left(x-1\right)=0\)
b)\(-5.\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}.\left(x-\dfrac{2}{3}\right)=x\)
c)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
d)\(9.\left(3x+1\right)^2=16\)