\(\frac{x+3}{7}=\frac{2-x}{3}\)
=>3(x+3)=7(2-x)
3x+9=14-7x
3x+7x=14-9
(3+7)x=5
10.x=5
x=5:10
x=0,5
\(\frac{x+3}{7}=\frac{2-x}{3}\)
=>3(x+3)=7(2-x)
3x+9=14-7x
3x+7x=14-9
(3+7)x=5
10.x=5
x=5:10
x=0,5
Tìm x biết : \(\left(\frac{1}{7}x-\frac{2}{7}\right)\left(\frac{-1}{5}x+\frac{3}{5}\right)\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
Tìm x biết:\(\frac{6}{x^2+2}+\frac{12}{x^2+8}=3-\frac{7}{x^2+3}\)
Tìm x, biết: \(\frac{6}{x^2+2}+\frac{12}{x^2+8}=3-\frac{7}{x^2+3}\)
Tìm x biết
a) \(\frac{x+7}{2010}+\frac{x+6}{2011}=\frac{x+5}{2012}+\frac{x+4}{2013}\)
b) \(\frac{11}{x^2+7}+\frac{23}{x^2+19}=3-\frac{7}{y+3}\)
Tìm x biết
a) \(\frac{x+7}{2010}+\frac{x+6}{2011}=\frac{x+5}{2012}+\frac{x+4}{2013}\)
b) \(\frac{11}{x^2+7}+\frac{23}{x^2+19}=3-\frac{7}{y+3}\)
Tìm x biết:
\(\frac{6}{x^2+2}+\frac{12}{x^2+8}=3-\frac{7}{x^2+3}\)
Tìm X. Biết
\(\frac{6}{x^2+2}+\frac{12}{x^2+8}=3-\frac{7}{x^2+3}\)
TÌm x biết:
\(\frac{6}{x^2+2}+\frac{12}{x^2+8}=3-\frac{7}{x^2+3}\)
Tìm x, biết
\(a.\frac{3}{2}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}+\frac{7}{9}\)
\(b.\left(x-\frac{1}{3}\right).\left(x+\frac{2}{5}\right)>0\)
Tìm x, biết
a)\(\frac{3}{2}-\frac{2}{7}< \frac{2}{3}x+\frac{3}{4}< \frac{1}{2}+\frac{7}{9}\)
b)\(\left(x-\frac{1}{3}\right).\left(x+\frac{2}{5}\right)>0\)