\(\frac{x+3}{2007}-\frac{x+3}{2008}=\frac{x+3}{2010}+\frac{x+3}{2009}\)
=> \(\frac{x+3}{2007}-\frac{x+3}{2008}-\frac{x+3}{2010}-\frac{x+3}{2009}=0\)
=> \(\left(x+3\right)\left(\frac{1}{2007}-\frac{1}{2008}-\frac{1}{2009}-\frac{1}{2010}\right)=0\)
=> x + 3 = 0
=> x = 0 - 3
=> x = -3
tìm x :
\(\frac{x +3}{2007}-\frac{x+3}{2008}=\frac{x+3}{2010}-\frac{x+3}{2009}\)
Tìm x biết :
\(\frac{x+3}{2007}\)- \(\frac{x+3}{2008}\)= \(\frac{x+3}{2010}\)- \(\frac{x+3}{2009}\)
Tìm x : \(\frac{x+4}{2007}+\frac{x+3}{2008}=\frac{x+2}{2009}+\frac{x+1}{2010}\)
Tìm số hữu tỉ x,biết : \frac{x+6}{2010}+\frac{x+5}{2009}=\frac{x+4}{2008}+\frac{x+4}{2007}
tìm x,biết:\(\frac{x+1}{2009}+\frac{x+2}{2008}=\frac{x+3}{2007}+\frac{x+4}{2006}\)
tìm x biết:\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
tìm x biết:
\(\frac{x-1}{2011}+\frac{x-2}{2010}+\frac{x-3}{2009}=\frac{x-4}{2008}\)
Tìm x biết:
\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
Tìm x biết :
\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
