Question

Tìm x biết :

\(\frac{x+3}{2007}\)- \(\frac{x+3}{2008}\)= \(\frac{x+3}{2010}\)- \(\frac{x+3}{2009}\)

Answer 1

\(\frac{x+3}{2007}-\frac{x+3}{2008}=\frac{x+3}{2010}-\frac{x+3}{2009}\)

\(\Leftrightarrow\)\(\frac{x+3}{2007}-\frac{x+3}{2008}-\frac{x+3}{2010}+\frac{x+3}{2009}=0\)

\(\Leftrightarrow\)\(\left(x+3\right)\left(\frac{1}{2007}-\frac{1}{2008}-\frac{1}{2010}+\frac{1}{2009}\right)=0\)

Vì \(\frac{1}{2007}-\frac{1}{2008}-\frac{1}{2010}+\frac{1}{2009}\ne0\)

Nên \(x+3=0\)

\(\Leftrightarrow\)\(x=-3\)

Vậy \(x=-3\)

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