áp dụng tính chất của dãy tỉ số bằng nhau ta có:
\(\frac{x+2}{x+6}=\frac{x+4}{x+5}=\frac{\left(x+2\right)-\left(x+4\right)}{\left(x+6\right)-\left(x+5\right)}=\frac{x+2-x-4}{x+6-x-5}=\frac{-2}{1}=-2\)
suy ra:
\(\frac{x+2}{x+6}=-2\Rightarrow x+2=-2.\left(x+6\right)\)
\(x+2=-2x-12\)
\(x+2x=-12-2\)
\(3x=-14\)
\(x=\frac{-14}{3}\)
Tìm x biết: \(\frac{x+1}{9}+\frac{x+4}{6}+\frac{x+5}{5}=\frac{x+2}{8}+\frac{x+3}{7}+\frac{x+6}{4}.\)
Tìm x biết \(\frac{2}{3}\left(\frac{3}{5}x+\frac{1}{2}\right)=\frac{4}{5}.\left(\frac{5}{6}x-\frac{4}{3}\right)+\frac{1}{2}x-\frac{4}{5}\)
tìm x biết :\(\frac{x-2}{x-4}=\frac{x-5}{x-6}\)
Tìm x biết \(\frac{x+1}{2}+\frac{x+1}{2}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
Tìm x biết:
a.
\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}...\frac{30}{62}.\frac{31}{64}=2^x\)
b.
\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^x\)
Tìm số hữu tỉ x,biết : \frac{x+6}{2010}+\frac{x+5}{2009}=\frac{x+4}{2008}+\frac{x+4}{2007}
Tìm x, biết:
\(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x
+1}{6}\)
Tìm x biết
a) (8-5x).(x+2)+4.(x-2).(x+1)+2.(x-2).(x+2)=0
b)\(\left(-\frac{2}{5}+x\right):\frac{7}{9}+\left(-\frac{3}{5}+\frac{5}{6}\right):\frac{7}{9}=0\)
c)\(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=1\frac{2003}{2004}\)
Tìm x biết :
a, \(\frac{x+5}{2010}+\frac{x+6}{2009}+\frac{x+7}{2008}=-3\)
b, \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+349}{5}=0\)
