Question

tìm x biết: \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

Answer 1

ta có:\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

\(\left(1+\frac{x+2}{327}\right)+\left(1+\frac{x+3}{326}\right)+\left(1+\frac{x+4}{327}\right)+\left(1+\frac{x+5}{324}\right)+\left(\frac{x+349}{5}-4\right)=0\)

\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

\(\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)

\(\left(x+329\right)=0\left(vì\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)>0\right)\)

\(x+329=0\Rightarrow x=-329\)